مشاهدة النسخة كاملة : ممكن حل لهذا التكامل
nour_eng_22
01-12-2010, 00:07
اريد حل لهذا التكامل العنيدددددددددد
e^-x (x^2 - 2x ) dx
http://www.mediafire.com/i/?bxzxgx8d7mm0p9f
nour_eng_22
01-12-2010, 00:08
http://www.mediafire.com/i/?bxzxgx8d7mm0p9f
يحل بطريقه التكامل بالتجزي مرتان
http://latex.codecogs.com/gif.latex?\fn_cs%20\120dpi%20\\\int%20(x^2-2x)e^{-x}dx=\int%20x^2e^{-x}dx-2\int%20xe^{-x}dx\\\\%20\text{let}%20\;%20u=x^2,%20dv=e^{-x},\Rightarrow%20du=2x,\;%20\text{and}%20\;v=-e^{-x}%20\\\text{In%20the%20first%20integral%20on%20th e%20LHS%20use%20the%20integration%20by%20parts%20f ormula%20}\\\\%20\boxed{%20\int%20udv=uv-\int%20vdu}\\\\%20\int%20(x^2-2x)e^{-x}dx=-x^2e^{-x}+2\int%20xe^{-x}dx-2\int%20xe^{-x}dx+C\\\\%20\therefore%20\int%20(x^2-2x)e^{-x}dx=\underline{\underline{-x^2e^{-x}+C}}%20{\color{red}%20\checkmark}
هذا والله تعالى اعلم
nour_eng_22
01-12-2010, 16:55
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