ثلاث مسائل فيزيائية ..؟!

[ماهررر]

السلام عليكم ورحمة الله وبركاته

ارجو حل هذه المسائل مع طريقة الحل

Three blocks, acted upon by an unbalanced force, are moving with an acceleration of
5 m/s2 as shown in the figure below, what is the net force acting on block (II)?

http://www.phys4arab.net/vb/attachment.php?attachmentid=11971&stc=1&d=1388864837
In the figure below, a force (FA) parallel to the ramp is required to slide a 25-kg box
a distance of 18 m at constant speed to the top of the ramp. What is the work done by
this force? (Assume no friction)
http://www.phys4arab.net/vb/attachment.php?attachmentid=11972&stc=1&d=1388865010

One ball is thrown straight up in the air and, at the same instant; another ball is
released from rest and allowed to fall. What graphs in the figure below represent the
motion of these balls? ("v" is the velocity and "t" is the time).
http://www.phys4arab.net/vb/attachment.php?attachmentid=11973&stc=1&d=1388865010

[خلف الجميلي]

تفضل حل السؤال الأول

http://www.phys4arab.net/vb/attachment.php?attachmentid=11970&d=1388862469

[خلف الجميلي]

إجابة السؤال الثاني :

w= mgh
w = 25 * 9.8 * 4.5 = 1102.5j

[خلف الجميلي]

إجابة السؤال الثالث هو :

1 و 2 يعني خيار a

[I'm physicist]

بارك الله فيك استاذنا الكريم
لكن لي تعليق على السؤال الاول حلك صحيح لكنه يريد القوة المحصلة على الجسم الثاني ومن حلك يتبين ان الجواب يساوي 10 نيوتن وليس 25 . ان كان جوابي خاطيء فارجو ارشادي للصواب وشكرا

[ام عبد الرحمن محمد]

بارك الله فيك استاذ خلف

محصلة القوة على الجسم الثاني = الكتلة × التسارع
= 2 × 5
= 10

[ماهررر]

بارك الله فيك استاذ خلف .. وبقية الاعضاء المشاركين


كما تفضلت .. السؤال الثاني والثالث.. الاجوبة صحيحة


السؤال الاول الجواب الصحيح 10 ! ولكني لم اقتنع ..؟؟؟؟

[خلف الجميلي]

نعم المحصلة على الكتلة II هي 10 كالتالي
P-Q=5×2=10N

الأخ ماهر لاحظ الجسم ذو الكتلة 2kg في الرسم تجد القوى المؤثرة عليه هي p و Q معاكسة لها في الاتجاه وتكون محصلة القوتين الفرق بينهما كالتالي

P-Q=ma=2×5=10N

[myy]

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