[د.امير]

Q6
Q is the quantity of heat, m is the mass of the body, Cx is the specific heat and T the temperature change. or
Q = m Cx ΔT
Heat lost by the unknown material = 0.125 kg Cx (22.4 – 90)
Heat gained by water = 0.326 kg * 4186 ( 22.4 – 20), specific heat of water is 4186 J kg-1 K-1
Assuming equilibrium, then the heat lost by the unknown material is the heat gained by water, or
Qunknown + Qwater =0
0.125 kg Cx (22.4 – 90) + 0.326 kg * 4186 ( 22.4 – 20) =0
8.45 Cx = 3275.1, or Cx= 387.6 J kg-1 K-1 specific heat of the unknown material