Q) A system of two particles m1=3 kg , vi= i+ j + 2k m/s and m2 =2kg , v2= 2j + j m/s
Find the total kinetic energy of the system using the following expressions:
T=□(1/( 2 ) mv_cm^2 ) + ∑▒□(1/2 m_(i v^(∖2) ) ) ……..1
T=□(1/( 2 ) mv_cm^2 ) + □(1/2 μv^2 ) ………..2
Where m=m1 + m2 , v-I is the relative velocity of particle i to Center mass ( CM), µ is the reduced mass , v is the relative velocity between the two particles m1 and m2 , and vcm is the velocity of the CM of the system.