3 -
Isochoric (constant volume ) heat addition process
P1/T1 = P2/T2
P2 = T2/T1 * P1
P1 = 13600*9.81 * 0.66 = 88054.6 Pa (0.88bar
T1 = 27 + 273 = 300 K
T2 = 250 + 273 = 523 K
P2 = 523/300 * 88054.6
P2 = 153508.5 Pa (1.535 bar
153508.5/(9.81 * 13600) = 115 cm