A race car travels 40 m/s around a banked (45 with the horizontal) circular (radius = 0.20 km) track. What is the magnitude of the resultant force on the 80 kg driver of this car?
a. 0.68 kN b. 0.64 kN c. 0.72 kN d. 0.76 kN e. 0.52 kN
ok>>>
I can guess that you want here the what so called the centripetal force
Fc = mv2/r = 80 *1600/200 = 640N = 0.64KN
regardless of having theta or not>>>
however you can calculate the reaction N as :
N sin(theta) = Fc and from which you can get: N= 896N nearly...
thanks