[m2007]

السلام عليكم ورحمة الله وبركاته

لو سمحتم اريد منكم حل هذه الاسئلة لمن يعرف الحل وجزيتم خيرا

Question1:
A parallel-plate capacitor with circular shaped plates, with a diameter of 4 cm and air-gap separation of 0.50 mm is connected to a 12 V battery, and fully charged. The battery is then disconnected, what is the charge on the capacitor?
Question 2:
Consider a charged parallel-plate capacitor. How can its capacitance be halved? Check all that apply from the list below and show how:

- Double the charge.
- Double the plate area.
- Double the plate separation.
- Halve the charge.
- Halve the plate area.
- Halve the plate separation.
Question 3:
Consider a charged parallel-plate capacitor. Which combination of changes would quadruple its capacitance and show how?
- Double the charge and double the plate area.
- Double the charge and double the plate separation.
- Halve the charge and double the plate separation.
- Halve the charge and double the plate area.
- Halve the plate separation and double the plate area.
- Double the plate separation and halve the plate area.

Question 4:
A parallel plate capacitor is formed from two square pieces of metal 0.040 m on a side. The plates are separated by 0.008 m, and the space between them is filled with insulating rubber, which has a dielectric constant of 6.7. When this capacitor is connected to a 25 volt battery, what is the magnitude of the charge on each plate?

[بكر سلمان]

السؤال الاول
السعة = ابسيلون * المساحة \ المسافة بين اللوحين

الشحنه = السعة * الجهد

[بكر سلمان]

السؤال الثاني
الحالة الاولى Double the plate separation. لان المواسعة تتناسب عكسيا مع المسافة بين اللوحين
الحالة الثانية Halve the plate area لان مساحة السطح تتناسب طرديا مع السعة

السعة لا تعتمد على الشحنه ولكنها تعتمد على الابعاد فقط طبعا وسماحية الوسط ( المادة بين اللوحين )

[khaled1966]

لوترجمة الأسئلة