[Obama08]

[align=center]بسم الله الرحمن الرحيم
we should find the time :
19.85*t - 4.33t^2 = 0 , t = 4.58 sec

x=33cos(65-28) *t - .5*g* sin28*t^2 , x=71.75m

To find velocity components:

Vx= 33cos(65-28) - g*sin28*t , Vx= 5.52 m/s
Vy= 33sin(65-28)-g*cos28*t Vy= -19.8 m/s
V=20.56 m/s

To find the direction of V:

tan(a)=-3.59 , (a) = -74.42[/align]

[align=center]:fantastic_new:[/align]

[KinG of KinGs]

المشاركة الأصلية كتبت بواسطة Obama08 [align=center]بسم الله الرحمن الرحيم we should find the time : 19.85*t - 4.33t^2 = 0 , t = 4.58 sec x=33cos(65-28) *t - .5*g* sin28*t^2 , x=71.75m To find velocity components: Vx= 33cos(65-28) - g*sin28*t , Vx= 5.52 m/s Vy= 33sin(65-28)-g*cos28*t Vy= -19.8 m/s V=20.56 m/s To find the direction of V: tan(a)=-3.59 , (a) = -74.42[/align] [align=center]:fantastic_new:[/align]

hi my friend ...Obama08

i am anew student in physics .... please can you explain more about this solution and write the equation which you use it tin the solution ... and again thank you.

[KinG of KinGs]

المشاركة الأصلية كتبت بواسطة Obama08 [align=center]بسم الله الرحمن الرحيم we should find the time : 19.85*t - 4.33t^2 = 0 , t = 4.58 sec x=33cos(65-28) *t - .5*g* sin28*t^2 , x=71.75m [/align] [align=center]:fantastic_new:[/align]

please obama 08 explane from where the sin28 it came in the equation xf = xi+vxit-.5axt^2.

in short , why are you write sin28.

[خنفسانة]

[align=center]ما فهمت شي، ممكن تترجمون ليي بالعربي[/align]:emot30_astonishe:

[جماااان]

اي و الله إذا ما عليكم أمر ترجموه عشان الكل يستفيد
مع خالص الشكر:emot19_thumbsup: