ملتقى الفيزيائيين العرب > قسم المناهج الدراسية > فيزياء المرحلة الجامعية. | ||
Help me :( |
الملاحظات |
|
أدوات الموضوع | انواع عرض الموضوع |
|
#1
|
|||
|
|||
![]() where is the diagram
I have posted this solution depending a graph i've imagined in my mind so if you have the diagram please post it so i can check if my answer is correct or not Block 1 mass=5.00 kg Fnet=m1a=Tension Block 2 mass=9.00kg Fnet=-m2a=Tension-m2g (the -a because the block is accelerating down Plug T=m1a into the 2nd equation -m2a=m1a - m2g Plug in values -9a=5a - 9*9.8 a=6.3 m/s/s Then using 1st equation ( or 2nd but 1st is much easier) m1a=T 5*6.3=T 31.5N = T Good luck |
الذين يشاهدون محتوى الموضوع الآن : 1 ( الأعضاء 0 والزوار 1) | |
انواع عرض الموضوع |
![]() |
![]() |
![]() |
|
|